solution

#include<iostream.h>
#include<conio.h>

int main()
{
 int sub1,sub2,sub3,sub4,sub5,percentage;
 cout<<"Enter marks of five subjects : ";
 cin>>sub1>>sub2>>sub3>>sub4>>sub5;
 percentage=(sub1+sub2+sub3+sub4+sub5)/5;

 if(percentage>=60)
  cout<<"Ist division";
 else if(percentage>=50)
  cout<<"IInd division";
 else if(percentage>=40)
  cout<<"IIIrd division";
 else
  cout<<"Fail" ;

 getch();
 return 0;
}