Addition of two numbers without using the Addition Operator

• The first technique uses the notion of negative multiplied by minus to get a positive result. a-(-b) becomes a+b in this case. 
• As a result, the screen shows the sum of variables a and b. The similar principle is applied in the second technique. The third technique use the predefined function abs().

Addition of two numbers

• The stdlib.h header file defines the abs() function. It returns a number's absolute value. The bitwise complement operator is utilised in the fourth approach. The integer N's bitwise complement is equal to -(N+1). As a result, a-(b)-1 equals a-(-(b+1)). a+b+1-1 => a+b+1-1 => a+b+1-1 => a+b+1-1 => a+b+1-1 =>

Program for Addition of two numbers without using the Addition Operator

#include<stdio.h>

#include<conio.h>

#include<stdlib.h>

int main()

{

  int x, y;

  printf("Enter two number: ");

  scanf("%d %d",&x,&y);

  // method 1

  printf("%d\n", x-(-y));

  // method 2

  printf("%d\n", -(-x-y));

  // method 3

  printf("%d\n", abs(-x-y));

  // method 4

  printf("%d", x-(~y)-1);

 getch();

}

Expected Output:-

Enter two number: 25

35

60